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2 March, 17:00

If 18.1 mLmL of 0.800 M HClM HCl solution are needed to neutralize 5.00 mLmL of a household ammonia solution, what is the molar concentration of the ammonia?

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  1. 2 March, 17:14
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    Concentration of ammonia = 3M

    Explanation:

    The reaction for the question is a neutralization reaction between HCl and NH₃

    The chemical equation for the reaction is given as

    HCl + NH₃ → NH₄CL

    1 : 1 1

    Volume of HCl = 18.1ml = 0.0181L

    Volume of NH₃ = 5ml = 0.005L

    Molar concentration of HCl=0.8M

    Molar Concentration of NH₃ = ?

    Number of moles (n) = Molar concentration * Volume

    n = C * V

    n of HCL = 0.8 * 0.0181

    n = 0.01448moles

    Since mole ration for the reaction from the balanced equation above is 1:1,

    n of NH₃ = 0.01448

    molar concentration (C) of NH₃ = n/v

    C of NH₃ = 0.01448/0.005

    C of NH₃=2.896

    C OF NH₃ = 3M
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