A student neutralized 16.4 milliliters of HCl by adding 12.7 milliliters of 0.620 M KOH. What was the molarity of the HCl acid?

(1) 0.168 M (3) 0.620 M

(2) 0.480 M (4) 0.801 M

Question

Jax Maldonado

Chemistry

24 September, 18:01

A student neutralized 16.4 milliliters of HCl by adding 12.7 milliliters of 0.620 M KOH. What was the molarity of the HCl acid?

(1) 0.168 M (3) 0.620 M

(2) 0.480 M (4) 0.801 M

+2

Answers (1)

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Deangelo Stevenson · Answer 1

Molarity is equal to the moles of solute over liters of solvent. In getting the molarity of HCl, you must know the formula for two solutions which is equal to M1V1 = M2V2. (16.4 milliliters of HCl) M1 = (12.7 milliliters) (0.620 M KOH) and you have 0.480M HCl. The answer is number 2.

A student neutralized 16.4 milliliters of HCl by adding 12.7 milliliters of 0.620 M KOH. What was the molarity of the HCl acid?(1) 0.168 M (3) 0.620 M(2) 0.480 M (4) 0.801 M

A student neutralized 16.4 milliliters of HCl by adding 12.7 milliliters of 0.620 M KOH. What was the molarity of the HCl acid?

(1) 0.168 M (3) 0.620 M

(2) 0.480 M (4) 0.801 M