Approximately how many grams of sodium chloride (NaCl) are required to prepare 500. mL of 3.00 M solution

First convert mL to L:

(500. mL) / (1000L) =.500L

Then convert molarity to moles:

(3.00M) (.500L) = 1.5mol NaCl

Then convert moles of NaCl to grams of NaCl by multiplying it by its molar mass:

(1.5mol NaCl) (58.44g/mol NaCl) = 87.66g NaCl are needed