Ask Question
20 June, 02:09

Solid potassium chlorate (kclo3) decomposes into potassium chloride and oxygen gas when heated. how many moles of oxygen form when 54.3 g completely decomposes?

+2
Answers (1)
  1. 20 June, 02:34
    0
    The formula for potassium chlorate is: 2KClO₃ → 2KCl + 3O₂

    If moles = mass : molar mass

    then moles of KClO₃ = 54.3 g : [ (39 * 1) + (35.5 * 1) + (16 * 3) ] g/mol

    = 54.3 g : (122.5 g) g/mol

    = 0.4433 mol

    Now the mole ratio of KClO₃ : O₂ is 2 : 3

    ∴ if moles of KClO₃ = 0.4433 mol

    then moles of O₂ = (0.4433 mol : 2) * 3

    = 0.6649 mol

    Now since mass = moles * molar mass

    ∴ the mass of oxygen produced = 0.6649 mol * (16 * 2) g/mol

    = 21.277 g

    ∴ the grams of oxygen gas produced when 54.3 grams of potassium chlorate is decomposed is ~ 21.28 g.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Solid potassium chlorate (kclo3) decomposes into potassium chloride and oxygen gas when heated. how many moles of oxygen form when 54.3 g ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers