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14 May, 05:08

0.055 grams of PbSO4 is dissolved in 200.00 grams of H2O.

1. What is the mass of the total solution?

2. What is the concentration of the PbSO4 in ppm?

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Answers (1)
  1. 14 May, 05:36
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    Solution's mass = 200.055 g

    [PbSO₄] = 275 ppm

    Explanation:

    Solute mass = 0.055 g of lead (II) sulfate

    Solvent mass = 200 g of water

    Solution mass = Solvent mass + Solution mass

    0.055 g + 200 g = 200.055 g

    ppm = μg of solute / g of solution

    We convert the mass of solute from g to μg

    0.055 g. 1*10⁶ μg / 1g = 5.5*10⁴μg

    5.5*10⁴μg / 200.055 g = 275 ppm

    ppm can also be determined as mg of solute / kg of solution

    It is important that the relation is 1*10⁻⁶

    Let's verify: 0.055 g = 55 mg

    200.055 g = 0.200055 kg

    55 mg / 0.200055 kg = 275 ppm
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