Explain how you would prepare a solution of sucrose with a molarity of 0.25.

Solution of 0.25 M is prepared in two steps,

1) Calculate Amount of Solute:

Molar Mass of Solute: 342.3 g/mol

As we know,

Molarity = Moles / 1 dm³

or,

Moles = Molarity * 1 dm³

Putting Values,

Moles = 0.25 mol. dm⁻³ * 1 dm³

Moles = 0.25 moles

Now, find out mass of sucrose,

As,

Moles = Mass / M. mass

or,

Mass = Moles * M. mass

Putting Values,

Mass = 0.25 mol * 342.3 g. mol⁻¹

Mass = 85.57 g

2) Prepare Solution:

Take Volumetric flask and add 85.57 g of sucrose in it. Then add distilled water up to the mark of 1 dm³. Shake well! The solution prepared is 0.25 M in 1 Liter.