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28 February, 12:47

According to the following reaction, how many grams of sulfur are formed when 37.4 g of water are formed?

2H₂S (g) + SO₂ (g) → 3S (s) + 2H₂O (l)

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  1. 28 February, 13:16
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    We see that the molar ratio of sulfur to water is:

    3 : 2

    We first compute the moles of water:

    moles = mass / Mr

    moles = 37.4 / 18

    moles = 2.08

    By the ratio, moles of sulfur:

    3.12

    Mr sulfur = 64

    mass = 3.12 x 64

    mass = 199.7 grams
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