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22 August, 13:25

1. The gas left in a used aerosol can is at a pressure of 1 atm at 27 (if this can is thrown into a fire, what is the internal pressure of the gas when its temperature reaches 927 (C?

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  1. 22 August, 13:50
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    4atm

    Explanation:

    Step 1:

    Data obtained from the question. This include the following:

    Initial pressure (P1) = 1atm

    Initial temperature (T1) = 27°C

    Final temperature (T2) = 927°C

    Final pressure (P2) = ... ?

    Step 2:

    Conversion of celsius temperature to Kelvin temperature.

    This can obtained as follow:

    T (K) = T (°C) + 273

    Initial temperature (T1) = 27°C

    Initial temperature (T1) = 27°C + 273 = 300K

    Final temperature (T2) = 927°C

    Final temperature (T2) = 927°C + 273 = 1200K

    Step 3:

    Determination of the new pressure of the gas.

    This can be obtained as follow:

    P1/T1 = P2/T2

    Initial pressure (P1) = 1atm

    Initial temperature (T1) = 300K

    Final temperature (T2) = 1200K

    Final pressure (P2) = ... ?

    1/300 = P2 / 1200

    Cross multiply to express in linear form

    300 x P2 = 1 x 1200

    Divide both side by 300

    P2 = 1200/300

    P2 = 4atm

    Therefore, the new pressure of the gas is 4atm.
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