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8 December, 17:25

Calculate the number of atoms in a 4.08 * 103 g sample of cesium.

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  1. 8 December, 17:54
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    Number of moles = mass/molar mass

    =4.08 / 132.9 = 0.031

    number of atoms = number of moles x avogadros constant

    =0.031 x 6.02 x 10^23

    =1.87x10^22
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