James was given a sample of sodium bicarbonate NaHCO3 in a weighing dish to analyze. His teacher asked him to find the percent of each element in the compound. He easily calculated the first three elements, but was stumped when he got to oxygen. What is the percent oxygen in the compound? Round to the nearest whole number.

Question

Amiah Winters

Chemistry

18 December, 05:51

James was given a sample of sodium bicarbonate NaHCO3 in a weighing dish to analyze. His teacher asked him to find the percent of each element in the compound. He easily calculated the first three elements, but was stumped when he got to oxygen. What is the percent oxygen in the compound? Round to the nearest whole number.

+5

Answers (1)

Know the Answer?

Violet Miles · Answer 1

This question could be answered easily if the results of the abundance of the other elements are given. You will just have to subtract the sum of all their abundances to 100. Since it's not given, the solution would just be:

Na = 23 g/mol * 1 = 23 g

H = 1 g/mol * 1 = 1 g

C = 12 g/mol * 1 = 12 g

O = 16 g/mol * 3 = 48 g

Total = 84 g

% O = 48/84 * 100 = 57.14%