During an experiment, the percent yield of calcium chloride from a reaction was 82.38%. Theoretically, the expected amount should have been 105 grams. What was the actual yield from this reaction? CaCO3 + HCl → CaCl2 + CO2 + H2O

Question

Susan Schultz

Chemistry

16 February, 23:31

During an experiment, the percent yield of calcium chloride from a reaction was 82.38%. Theoretically, the expected amount should have been 105 grams. What was the actual yield from this reaction? CaCO3 + HCl → CaCl2 + CO2 + H2O

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Answers (1)

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Goose · Answer 1

Actual yield = 86.5g

Explanation:

Percent yield = 82.38%

Theoretical yield = 105g

Actual yield = x

Equation of reaction,

CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

Percentage yield = (actual yield / theoretical yield) * 100

82.38% = actual yield / theoretical yield

82.38 / 100 = x / 105

Cross multiply and make x the subject of formula

X = (105 * 82.38) / 100

X = 86.499g

X = 86.5g

Actual yield of CaCl₂ is 86.5g