In experiment 1, how many moles of benzoic acid are present? how many moles of sodium bicarbonate are contained in 1 ml of a 10% aqueous solution? (a 10% solution has 1 g of solute in 9 ml of solvent.) is the amount of sodium bicarbonate sufficient to react with all of the benzoic acid?

Question

Zechariah Preston

Chemistry

17 September, 10:58

In experiment 1, how many moles of benzoic acid are present? how many moles of sodium bicarbonate are contained in 1 ml of a 10% aqueous solution? (a 10% solution has 1 g of solute in 9 ml of solvent.) is the amount of sodium bicarbonate sufficient to react with all of the benzoic acid?

+4

Answers (1)

Know the Answer?

Dillon · Answer 1

First, let us calculate the moles of solute or sodium bicarbonate is in the 1 ml solution.

moles = 1 mL * (1 g / 9 mL) = 0.11 moles

The molar mass of sodium bicarbonate is 84 g/mol, therefore the mass is:

mass = 0.11 moles * 84 g/mol

mass = 9.33 g