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11 September, 11:10

A gas with a volume of 4.0 liters at a pressure of 205 kilopascals is allowed to expand to a volume of 12.0 liters. What will the pressure in the container be if the temperature remains constant?

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  1. 11 September, 11:32
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    Boyle's law p1V1=p2V2

    p2 = (p1V1) / V2

    p2 = (205*10^3 Pa * 4*10^-3 m^3) / (12*10^-3 m^3)

    p2 = 68333 Pa
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