Find the pH of a 0.00580 M solution of the strong

baseKOH.

11.76

Explanation:

Potassium hydroxide is a strong base that dissociates completely according to the following reaction.

KOH (aq) → K⁺ + OH⁻

Then, the concentration of OH⁻ will be 0.00580 M.

The pOH of the solution is:

pOH = - log [OH⁻]

pOH = - log 0.00580 = 2.24

We can calculate the pH using the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 - 2.24 = 11.76