What is the molarity of a

1.5 liter solution prepared using

4.6 grams of HCI?

0.084 M

Explanation:

Molarity is (moles of solute) / (liters of solvent)

Convert grams of HCl to moles.

(4.6 g) / (36.458 g/mol) = 0.126 mol

Divide moles by liters.

(0.126 mol) / (1.5 L) = 0.084 M