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16 December, 05:16

In a solution with a pH of 4, the [OH-] is:

1x 10-10

1x 10-4

10

- 1x 10-8

+3
Answers (1)
  1. 16 December, 05:28
    0
    1 x 10^-4

    Explanation:

    Use the equation pH = - log[OH-}

    Rearranging it [OH-] = 10^-pH

    Plugging in we get [OH-] = 1 x 10^-4
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