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1 April, 19:17

What is the mass of a sample of pure gold containing 3.00 x 1024 gold atoms?

a. 981 g

b. 196.97 g

c. 39.5 g

d. 6.56 x 10^-23 g

e. 1.52 x 10^22 g

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  1. 1 April, 19:46
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    Answer: The mass is 980.6g of Gold.

    Explanation:

    We begin by looking for the number of moles equivalent to 3.0 x 10^24 gold atoms.

    Using the Avogadro's number,

    6.02 x 10^23 atoms of gold make up 1 mole of gold.

    3.0 x 10^24 atoms would make up: 1 / 6.02 x 10^23 x 3.0 x 10^24 = 4.98moles.

    Now that we know the number of moles, we can then look for the mass using the formular:

    Moles = mass / molar mass

    4.98 = mass / 196.9 (atomic mass of gold)

    Making "mass" the subject of formula : mass = 4.98 x 196.9 = 980.6g
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