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29 October, 01:56

The decomposition of baking soda (NaHCO3) is given in this reaction: 2NaHCO3 → Na2CO3 + H2O + CO2 If 8 moles of baking soda decompose, how many moles of Na2CO3 are produced? 1 2 4 8

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  1. 29 October, 02:22
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    4 moles of Na2CO3

    2 NaHCO3 = Na2CO3+H2O+CO2

    8mol NaHCO3 * 1mol Na2CO3/2mol NaHCO3 = 4mol Na2CO3
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