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22 March, 11:59

What is the total amount of heat absorbed by 100.0

grams of water when the temperature of the water is

increased from 30.0°C to 45.0°C?

A) 418 J

B) 6270 J

C) 12 500 J

D) 18 800 J

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Answers (1)
  1. 22 March, 12:09
    0
    Option (B) 6270J

    Explanation:

    The following were obtained from the question:

    M = 100g

    T1 = 30°C

    T2 = 45°C

    ΔT = 45 - 30 = 15°C

    C = 4.18J/g°C

    Q=?

    Q = MCΔT

    Q = 100 x 4.18 x 15

    Q = 6270J

    Therefore, the total amount of heat absorbed is 6270J
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