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16 October, 15:06

What is the molality of a d-mannose solution prepared by dissolving 45.0 g of d-mannose, c6h12o6, in 125.9 g of water?

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  1. 16 October, 15:18
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    Molality is a unit of concentration that represents the moles of solute per kilogram of solvent. The solvent here is water.

    Mass of solvent in kg = 125.9 g * 1 kg/1000 g = 0.1259 kg

    The moles of d-mannose knowing that its molar mass is 180.156 g/mol,

    Moles solute = 45 g * 1 mol/180.156 g = 0.2498 mol

    Thus,

    Molality = 0.2498/0.1259 = 1.98 m
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