For the reaction 2ch4 (g) ⇌c2h2 (g) + 3h2 (g) k = 0.135 at 1608 ∘c. what is kp for the reaction at this temperature? express your answer numerically.

3.3 x 10⁷.

Explanation:

For the reaction: 2CH₄ (g) ⇄ C₂H₂ (g) + 3H₂ (g),

Kc = 0.135 at 1608 °C.

To get Kp, we can use the relation:

Kp = Kc (RT) ∧Δn.

R is the general gas constant = 8.314 J/mol. K.

T is the temperature of the vessel = 1608 °C + 273 = 1881.0 K.

Δn = no. of moles of gases in products - no. of moles of gases in the reactants = 4 - 2 = 2.

∴ Kp = Kc (RT) ∧Δn = (0.135) [ (8.314) (1881.0 K) ]² = 3.3 x 10⁷.