How many liters of a 3.67 M K2SO4 solution are needed to provide 57.3 g of K2SO4 (molar mass 174.01 g/mol) ? Recall that M is equivalent to mol/L.

Answer: Amount of volume needed in Litres is 0.09L

Explanation:

Given that the concentration in Mol/L = 3.67M

Mass of K2SO4 = 57.3g

Molar mass of K2SO4 = 174.01g/mol

From stochiometry,

Mole = Mass/Molar mass

Mole = 57.3/174.01 = 0.33mol.

Concentration in mol/L=

Mole/volume

3.67=0.33/volume

Volume = 0.33/3.67

Volume = 0.09L

Therefore the volume of K2SO4 needed is 0.09L