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4 March, 08:42

If 1.30 grams of a protein (non - electrolyte) are added to a 100.0 mL of water, the osmotic pressure of the resulting solution is 0.0074 atm at 298 K. What is the molar mass of the protein?

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  1. 4 March, 09:08
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    M = 0.43 * 10⁵ g/mol

    Explanation:

    Given dа ta:

    Mass of protein = 1.30 g

    Volume of water = 100.0 mL (100/1000 = 0.1 L)

    Pressure of solution = 0.0074 atm

    Temperature = 298 K

    Molar mass of protein = ?

    Solution:

    Formula:

    PV = nRT

    n = PV / RT

    n = 0.0074 atm * 0.1 L / 0.0821 atm. L / mol. K * 298 K

    n = 0.00074 / 24.5 / mol

    n = 3.0 * 10⁻⁵ mol

    Molar mass of protein:

    Number of moles = mass / molar mass

    3.0 * 10⁻⁵ mol = 1.30 g / M

    M = 1.30 g / 3.0 * 10⁻⁵ mol

    M = 0.43 * 10⁵ g/mol
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