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25 November, 10:03

How many grams of water do you have to decompose if you want to prepare 34.7 g of oxygen?

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  1. 25 November, 10:19
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    Try this solution:

    The equation of the reaction is:

    2H₂O⇒2H₂↑+O₂↑ where m (O₂) = 34.7gr.

    M (O₂) = 16*2=32 (gr./mol);

    ν (O₂) = m (O₂) / M (O₂) = 34.7/32=1.084375 (mol).

    According to the equation of the reaction ν (H₂O) = 2ν (O₂) = 2*1.084375=2.16875 (mol);

    M (H₂O) = 2+16=18 (gr./mol).

    m (H₂O) = M (H₂O) * ν (H₂O) = 18*2.16875=39.0375 gr.

    Answer: 39.0375 gr.
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