Ask Question
29 September, 04:05

Identify the limiting reactant when 1.78 gram of oxygen reacts with 2.16 grams of hydrogen to produce water.

+1
Answers (1)
  1. 29 September, 04:22
    0
    oxygen is limiting reactant.

    Explanation:

    Given dа ta:

    Mass of oxygen = 1.78 g

    Mas of hydrogen = 2.16 g

    Limiting reactant = ?

    Solution:

    Chemical equation:

    2H₂ + O₂ → 2H₂O

    Number of moles of oxygen:

    Number of moles = mass / molar mass

    Number of moles = 1.78 g / 32 g/mol

    Number of moles = 0.06 mol

    Number of moles of hydrogen:

    Number of moles = mass / molar mass

    Number of moles = 2.16 g / 2 g/mol

    Number of moles = 1.08 mol

    No we will compare the moles of oxygen and hydrogen with water.

    O₂ : H₂O

    1 : 2

    0.06 : 2*0.06 = 0.12 mol

    H₂ : H₂O

    2 : 2

    1.08 : 1.08

    Number of moles of water produced by oxygen are less so oxygen will be limiting reactant.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Identify the limiting reactant when 1.78 gram of oxygen reacts with 2.16 grams of hydrogen to produce water. ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers