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31 December, 19:50

If 97.7 ml of silver nitrate solution reacts with excess potassium chloride solution to yield 0.326 g of precipitate, what is the molarity of silver ion in the original solution?

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  1. 31 December, 20:13
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    The complete balanced chemical reaction is written as:

    AgNO3 + KCl - - - > AgCl + KNO3

    where AgCl is our precipitate

    So calculating for moles of AgCl produced: MM AgCl = 143.5 g/mol

    moles AgCl = 0.326 g / (143.5 g/mol) = 2.27 x 10^-3 mol

    we see that there is 1 mole of Ag per 1 mole of AgCl so:

    moles Ag = 2.27 x 10^-3 mol

    The molarity is simply the ratio of number of moles over volume in Liters, therefore:

    Molarity = 2.27 x 10^-3 mol / 0.0977 L

    Molarity = 0.0233 M
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