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29 March, 15:39

When 0.1523 g of liquid pentane (c_5 5 h_{12} 12 ) combusts in a bomb calorimeter, the temperature rises from 23.7^{/circ} ∘ c to 29.8 ^{/circ} ∘

c. what is / deltaδu_{rxn} rxn for the reaction in kj/mol pentane? the heat capacity of the bomb calorimeter is 5.23 kj/^{/circ} ∘

c?

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  1. 29 March, 16:08
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    q solution = m x c x Î"T m solution = 0.468 g pentane + 1,000 g H2O = 1,000.468 g solution c solution = c water = 4.184 J/g.°C Î"T = Tf - Ti = 23.65 °C - 20.45 °C = 3.20 °C q solution = 1,000.468 g x 4.184 J/g.°C x 3.20 °C = 13.395 kJ
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