Ask Question
18 January, 01:43

Diatomic O2 can react with the element magnesium to form magnesium oxide (MgO). The balanced chemical equation is: O2 + 2 Mg → 2 MgO If 97.2 g grams of magnesium totally reacted with more than enough O2, how many moles of MgO would be expected to form?

+4
Answers (1)
  1. 18 January, 02:07
    0
    We expected 4 moles of MgO to be formed. (This is 161.2 grams)

    Explanation:

    Step 1: The balanced equation

    O2 + 2 Mg → 2 MgO

    Step 2: Data given

    mass of Mg = 97.2 grams

    O2 = in excess

    Molar mass of Mg = 24.3 g/mol

    Molar mass of O2 = 32 g/mol

    Molar mass of MgO = 40.3 g/mol

    Step 3: Calculate moles of Mg

    moles Mg = 97.2 / 24.3 g/mol

    moles Mg = 4 moles

    Mg is the limiting reactant. It will completely react (4 moles). O2 is in excess. There will react 2 moles of 02.

    Step 4: Calculate moles of MgO

    For 2 moles Mg consumed, we need 1 mole O2 to produce 2 moles of MgO

    For 4 moles of Mg consumed, we have 4 moles of MgO produced.

    We expected 4 moles of MgO to be formed. (This is 161.2 grams)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Diatomic O2 can react with the element magnesium to form magnesium oxide (MgO). The balanced chemical equation is: O2 + 2 Mg → 2 MgO If ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers