1.6 moles of phosphorus, P8 reacts with oxygen gas to form tetraphosphorus decoxide. How many grams of P4O10 are formed? P8 + 5O2 - - > 2P4O10

Question

Adison

Chemistry

10 June, 03:58

1.6 moles of phosphorus, P8 reacts with oxygen gas to form tetraphosphorus decoxide. How many grams of P4O10 are formed? P8 + 5O2 - - > 2P4O10

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Kailyn Curtis · Answer 1

The balanced chemical reaction are as follows:

P8 + 5O2 - - > 2P4O10

We are given the amount of P8 to be used in the reaction. We use this to calculate what is asked. We do as follows:

1.6 mol P8 (2 mol P2O10 / 1 mol P8) (283.89 g / mol) = 908.45 g P4O10 produced