1. What is the mass of 25.0 L of neon at STP?

Answer: m = 22.2 g Ne

Explanation: First find the moles of Ne using Ideal Gas Law and derive for n. So from PV = nRT the mole is derived as n = PV / RT

n = PV / RT

= 1 atm (25 L) / 0.0821 L. atm /

mole. K (273 K)

= 1.11 moles Ne

Convert it to mass using the molar mass of Neon

1.11 moles Ne x 20 g Ne / 1 mole Ne

= 22.2 g Ne