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2 December, 16:27

568 cm3 of chlorine at 25° C will occupy what volume at - 25° C while the pressure remains constant?

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  1. 2 December, 16:49
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    474.3 cm³

    Explanation:

    Given dа ta:

    Initial volume of chlorine gas = 568 cm³

    Initial temperature = 25°C

    Final volume = ?

    Final temperature = - 25°C

    Solution:

    Initial temperature = 25°C (25+273 = 297 K)

    Final temperature = - 25°C (-25 + 273 = 248 K)

    The given problem will be solve through the Charles Law.

    According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

    Mathematical expression:

    V₁/T₁ = V₂/T₂

    V₁ = Initial volume

    T₁ = Initial temperature

    V₂ = Final volume

    T₂ = Final temperature

    Now we will put the values in formula.

    V₁/T₁ = V₂/T₂

    V₂ = V₁T₂/T₁

    V₂ = 568 cm³ * 248 K / 297 K

    V₂ = 140864 cm³. K / 297 K

    V₂ = 474.3 cm³
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