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6 October, 20:03

Determine the change in volume that takes place when a 2.00 L sample of N2 gas is heated from 250 C to 500 C.

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  1. 6 October, 20:09
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    V₂ = 2.96 L

    Explanation:

    Given dа ta:

    Initial volume = 2.00 L

    Initial temperature = 250°C

    Final volume = ?

    Final temperature = 500°C

    Solution:

    First of all we will convert the temperature into kelvin.

    250+273 = 523 k

    500+273 = 773 k

    According to Charles's law,

    V∝ T

    V = KT

    V₁/T₁ = V₂/T₂

    V₂ = T₂V₁/T₁

    V₂ = 2 L * 773 K / 523 k

    V₂ = 1546 L. K / 523 k

    V₂ = 2.96 L
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