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13 March, 18:56

What mass of propane (c3h8 (g)) must be burned to supply 2775 kj of heat? the standard enthalpy of combustion of propane at 298 k is - 2220 kj · mol-1?

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  1. 13 March, 19:08
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    Answer is: 55.125 grams of propane must be burned.

    Balanced chemical reaction: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.

    Make proportion: 1 mol (C₃H₈) : 2220 kJ = n (C₃H₈) : 2775kJ.

    n (C₃H₈) = 2775 kJ·mol : 2220 kJ.

    n (C₃H₈) = 1.25 mol.

    m (C₃H₈) = n (C₃H₈) · M (C₃H₈).

    m (C₃H₈) = 1.25 mol · 44.1 g/mol.

    m (C₃H₈) = 55.125 g.

    n - amount of substance.
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