In an acid-base neutralization reaction 43.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution. what is the concentration of the h2so4 solution?'

The neutralization reaction between potassium hydroxide and sulfuric acid is as follows

2KOH + H2SO4 - - - > K2SO4 + 2H2O

number of moles of KOH = (43.74 x 0.500) / 1000 = 0.02187 moles

the reacting ratio of KOH to H2SO4 is 2:1 therefore the moles of H2SO4 is = 0.021187/2 = 0.01094 moles

concentration (molarity) = (0.01094/50) x 1000 = 0.2188M