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18 April, 07:28

What is the partial pressure of argon, par, in the flask? express your answer to three significant figures and include the appropriate unit?

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  1. 18 April, 07:57
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    Given which are missing in your question:

    the flask is filled with 1.45 g of argon at 25 C°

    So according to this formula (Partial pressure):

    PV = nRT

    first, we need n, and we can get by substitution by:

    n = 1.45/mass weight of argon

    = 1.45 / 39.948 = 0.0363 mol of Ar

    we have R constant = 0.0821

    and T in kelvin = 25 + 273 = 298

    and V = 1 L

    ∴ P * 1 = 0.0363 * 0.0821 * 298 = 0.888 atm
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