When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? when 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? 0.880 mol 0.440 mol 0.330 mol 0.220 mol 0.110 mol?

Question

Saul

Chemistry

8 May, 14:44

When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? when 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? 0.880 mol 0.440 mol 0.330 mol 0.220 mol 0.110 mol?

+3

Answers (1)

Know the Answer?

Chelsea Landry · Answer 1

The moles of aluminum produced when 0.440 moles reacted is calculated as below

write the balanced equation for reaction

2Al+3Cl2 = 2Al2Cl3

by use of mole ratio between Al to Al2Cl3 which is 2:2 the moles of Al2Cl3

= 0.440 x2/2 = 0.440 moles of AI2CI3