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4 November, 20:05

When 10 liters of a gas at 1 atm is compressed to 3 liters at constant temperature, what property of the gas changes?

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  1. 4 November, 20:31
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    We know that at state 1, we can describe the gas at STP by P1V1=n1RT1

    We change the volume, so now there is a second state, state 2 that can be described as

    P2V2=n2RT2

    We are told that temperatures are constant and since no gas is lost then moles don't change. Hence n1T1=n2T2. So rearrange the equations as follows

    P1V1/R=n1T1

    P2V2/R=n2T2

    Set them equal per my explanation above:

    P1V1/R=P2V2/R

    Now multiply by R on both sides

    P1V1=P2V2

    We want to find the pressure at state 2

    P1V1/V2=P2

    (1 atm) (10L) / (3L) = 3.33 atm = P2
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