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Chemistry
17 January, 11:14
How many aluminum atoms are in 3.78 g of aluminum?
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Jovanni Camacho
17 January, 11:30
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Molar mass of aluminum = 26.982 g/mol.
1 mol of Al = 26.9≈27g = 6.02*10²³ atoms [ avogadro's number]
meaning
1 g | Al = 6.02/27 * 10²³ atoms
so 3.78g | Al = 6.02*3.78]/27 * 10²³
= 0.8428 * 10²³ atoms
= 8.428 * 10²² atoms
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