HCl + KOH - --> KCl + H20 hOw many moles of HCl required to produce 5.59 x 10-3 moles of KCl?

Question

Damon

Chemistry

8 October, 08:24

HCl + KOH - --> KCl + H20 hOw many moles of HCl required to produce 5.59 x 10-3 moles of KCl?

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Answers (1)

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Ben Juarez · Answer 1

5.59x10^-3 moles

Explanation:

The balanced equation for the reaction is given below:

HCl + KOH - > KCl + H2O

Now we can obtain the number of mole of HCl required to produce 5.59x10^-3 moles of KCl as follow:

From the balanced equation above, 1 mole of HCl produced 1 mole of KCl.

Therefore, 5.59x10^-3 moles of HCl will also produce 5.59x10^-3 moles of KCl.

From the illustration made above, we can see evidently that 5.59x10^-3 moles of HCl is required to produce 5.59x10^-3 moles of KCl