How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in the single replacement reaction below? Be sure to show the work that you did to solve this problem.

Question

Jace Burgess

Chemistry

19 February, 05:21

How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in the single replacement reaction below? Be sure to show the work that you did to solve this problem.

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Answers (1)

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June Carpenter · Answer 1

Answer is: 25.84 milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d (Na) = 0.97 g/mL; density of sodim.

m (NaOH) = 43.6 g; mass of sodium hydroxide.

n (NaOH) = m (NaOH) : M (NaOH).

n (NaOH) = 43.6 g : 40 g/mol.

n (NaOH) = 1.09 mol; amount of sodium hydroxide.

From chemical reaction: n (NaOH) : n (Na) = 2 : 2 (1: 1).

n (Na) = 1.09 mol.

m (Na) = 1.09 mol · 23 g/mol.

m (Na) = 25.07 g; mass of sodium.

V (Na) = m (Na) : d (Na).

V (Na) = 25.07 g : 0.97 g/mL.

V (Na) = 25.84 mL.