Identify the precipitate or lack thereof for the following:CaCl2 (aq) + K2CO3 (aq) - -> CaCO3 + 2KClA) CaCO3B) KClC) No precipitateFeCl2 (aq) + (NH4) 2SO4 (aq) - -> FeSO4 + 2NH4ClA) FeSO4B) NH4ClC) No precipitate

A) CaCO₃

C) No precipitate

Explanation:

To answer these questions we need to consider the solubility rules.

Identify the precipitate or lack thereof for the following:

CaCl₂ (aq) + K₂CO₃ (aq) ⇒ CaCO₃ (s) + 2 KCl (aq)

Group II carbonates are insoluble. Thus, CaCO₃ is insoluble. Salts containing Group I cations are soluble. Thus, KCl is soluble.

FeCl₂ (aq) + (NH₄) ₂SO₄ (aq) ⇒ FeSO₄ (aq) + 2 NH₄Cl (aq)

Most sulfates are soluble. Thus, FeSO₄ is soluble. Salts containing the ammonium ion are soluble. Thus, NH₄Cl is soluble.