A gas of unknown identity diffuses at a rate of 83.3 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate of 102 mL/s. Calculate the molecular mass of the unknown gas. Give your answers in units of g/mol to three significant figures.

Question

Adalynn Singleton

Chemistry

1 May, 16:05

A gas of unknown identity diffuses at a rate of 83.3 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate of 102 mL/s. Calculate the molecular mass of the unknown gas. Give your answers in units of g/mol to three significant figures.

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Joel Benson · Answer 1

The rate of diffusion increases as the concentration difference increases. It related to the molar mass of a substance by KMT and the Graham's law of diffusion which is as follows:

Rate1 / Rate2 = (√ MM2 / √ MM1)

83.3 / 102 = √ 44.01 / MM1

MM1 = 65.99 g / mol