Using the equation below, calculate the number of grams of H2O that are formed from the reaction of 34.0 g of NH3.

4NH3 + 3O2 - -> 2N2 + 6H2O

54 grams of H₂O

Explanation:

4NH₃ + 3O₂ → 2N₂ + 6H₂O

Ratio is 4:6.

Let's convert the mass of ammonia in moles

Mass / Molar mass = Mol

34 g / 17 g/m = 2 moles

If 4 moles of ammonia are needed to produce 6 mol of water

2 mol of NH₃ will produce (2.6) / 4 = 3 moles

Molar mass water = 18 g/m

Mass = mol. molar mass → 3 m. 18 g/m = 54 grams