A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?

Question

Brock

Chemistry

14 December, 14:45

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?

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Giovanny Lawrence · Answer 1

Use Charles's Law., which relates volume and temperature for gases at constant pressure. = > V1/T1 = V2/T2. This formula requires the use of absolute temperatures=> T1 = 25.0 + 273.15K = 298.15K, and T2 = 40.0 + 273.15K = 313.15K. Therefore: 3.50 L / 298.15K = x / 313.15K = > x = 3.50L * 313.15K / 298.15K = 3.68 L. Answer: 3.68 L