What is the hydronium ion concentration in a solution prepared by mixing 150.00 ml of 0.10 mhcn with 150.00 ml of 0.030 mnacn? assume that the volumes of the solutions are additive and that ka=4.910-10. what is the hydronium ion concentration in a solution prepared by mixing 150.00 of 0.10 with 150.00 of 0.030? assume that the volumes of the solutions are additive and that. 4.910-10m 7.010-6m 1.610-9m 2.4*1010m?

Question

Alvin Weaver

Chemistry

18 October, 03:27

What is the hydronium ion concentration in a solution prepared by mixing 150.00 ml of 0.10 mhcn with 150.00 ml of 0.030 mnacn? assume that the volumes of the solutions are additive and that ka=4.910-10. what is the hydronium ion concentration in a solution prepared by mixing 150.00 of 0.10 with 150.00 of 0.030? assume that the volumes of the solutions are additive and that. 4.910-10m 7.010-6m 1.610-9m 2.4*1010m?

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Mariam Mccarty · Answer 1

Answer is: 1.6*10-9m.

This is buffer solution, so use Henderson-Hasselbalch equation:

V (solution) = 150 mL + 150 mL = 300 mL : 1000 mL/L = 0.3 L.

c (HCN) = ck = 0.15 L · 0.1 M / 0.3 L = 0.05 M.

c (NaCN) = cs = 0.15 L · 0.03 M / 0.3 M = 0.015 M.

[H⁺] = Ka · (ck/cs).

[H⁺] = 4.9·10⁻¹⁰ · (0.05 M : 0.015 M).

[H⁺] = 1.63·10⁻⁹ M.