GeF3H is formed from GeH4 and GeF4 in the combination reaction: GeH4 + 3GeF4 - > 4GeF3H. If the reactiln yield is 92.6%, how many moles of GeF4 are needed to produce 8 mol of GeF3H?

Answer is: 6,48 mol of GeF₄ are needed.

Chemical reaction: GeH₄ + 3GeF₄ → 4GeF₃ H.

n (GeF₃H) = 8 mol.

n (GeF₄) = ?

from chemical reaction: n (GeF₃H) : n (GeF₄) = 4 : 3.

8 mol : n (GeF₄) = 4 : 3.

4n (GeF₄) = 24 mol.

n (GeF₄) = 6 mol : 0,926.

n (GeF₄) = 6,48 mol.