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18 June, 19:56

A solution has a pH of 2.5. What is its [OH-]?

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  1. 18 June, 20:05
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    POH=14-pH=14-2.5=11.5 pH=-log[H+] 2.5=-log [H+] [H+]=10^-5/2 [OH-]=10^ (14-5/2) = 10^23/2
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