If 250.0 ml of a 0.96 m solution of acetic acid (c2h4o2 are diluted to 800.0 ml, what will be the approximate molarity of the final solution?

a. 0.19 m strike reset

b. 0.24 m strike reset

c. 0.30 m strike reset

d. 0.77 m strike reset

The answer is c. 0.30 m strike reset.

Calculate the concentration of the solution after the dilution.

C1 * V1 = C2 * V2

The initial solution:

C1 = 250 mL

V1 = 0.96 M

The final solution:

C2 = ?

V2 = 800 mL

250 mL * 0.96 M = C2 * 800 mL

C2 = 250 mL * 0.96 M / 800 mL

C2 = 0.30 M