Ask Question
16 June, 13:13

How many milliliters of a 0.7% stock solution are required to make 2 l of 0.2% solution? how many ml of solvent will be required to carry out the dilution?

+1
Answers (1)
  1. 16 June, 13:19
    0
    1. To solve this question, you need to equalize the mass of solute for both solution. The calculation would be:

    mass of solute = volume*concentration

    mass1=mass2

    volume1 * concentration1 = volume2 * concentration2

    volume1 * 0.7% = 2L * (1000ml/L) * 0.2%

    volume1 = 2000ml * (0.2%/0.7%)

    volume1 = 571.429 ml

    2. Since you already have the volume of stock needed, you just need to subtract it from the total solution volume to count the number of solvents needed.

    new solution volume = stock volume + diluting solvent volume

    2L * 2000ml/L = 571.429ml + diluting solvent volume

    diluting solvent volume = 2000ml - 571.429 ml = 1428.571ml
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How many milliliters of a 0.7% stock solution are required to make 2 l of 0.2% solution? how many ml of solvent will be required to carry ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers