The mass of amu of 710 iron atoms

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Anna Simpson

Chemistry

8 November, 02:11

The mass of amu of 710 iron atoms

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Marquise Little · Answer 1

The atomic mass unit of 710 Fe atoms would be equal to 41125 amu. We calculate this by first dividing with the avogadro's number which is 6.022x10^23. We obtain the number of moles, then we multiply with the molar mass to obtain grams. Lastly, divide with 1.6x10^-24 to obtain amu.